Optimal. Leaf size=304 \[ -\frac{2 b^2 \sqrt{a^2+2 a b x+b^2 x^2} \sqrt{d+e x} (-3 a B e-A b e+4 b B d)}{e^5 (a+b x)}-\frac{6 b \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e) (-a B e-A b e+2 b B d)}{e^5 (a+b x) \sqrt{d+e x}}+\frac{2 \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)^2 (-a B e-3 A b e+4 b B d)}{3 e^5 (a+b x) (d+e x)^{3/2}}-\frac{2 \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)^3 (B d-A e)}{5 e^5 (a+b x) (d+e x)^{5/2}}+\frac{2 b^3 B \sqrt{a^2+2 a b x+b^2 x^2} (d+e x)^{3/2}}{3 e^5 (a+b x)} \]
[Out]
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Rubi [A] time = 0.468858, antiderivative size = 304, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 35, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.057 \[ -\frac{2 b^2 \sqrt{a^2+2 a b x+b^2 x^2} \sqrt{d+e x} (-3 a B e-A b e+4 b B d)}{e^5 (a+b x)}-\frac{6 b \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e) (-a B e-A b e+2 b B d)}{e^5 (a+b x) \sqrt{d+e x}}+\frac{2 \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)^2 (-a B e-3 A b e+4 b B d)}{3 e^5 (a+b x) (d+e x)^{3/2}}-\frac{2 \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)^3 (B d-A e)}{5 e^5 (a+b x) (d+e x)^{5/2}}+\frac{2 b^3 B \sqrt{a^2+2 a b x+b^2 x^2} (d+e x)^{3/2}}{3 e^5 (a+b x)} \]
Antiderivative was successfully verified.
[In] Int[((A + B*x)*(a^2 + 2*a*b*x + b^2*x^2)^(3/2))/(d + e*x)^(7/2),x]
[Out]
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Rubi in Sympy [A] time = 55.5699, size = 320, normalized size = 1.05 \[ \frac{16 b^{2} \sqrt{d + e x} \sqrt{a^{2} + 2 a b x + b^{2} x^{2}} \left (3 A b e + 5 B a e - 8 B b d\right )}{15 e^{4} \left (a e - b d\right )} + \frac{32 b^{2} \sqrt{d + e x} \sqrt{a^{2} + 2 a b x + b^{2} x^{2}} \left (3 A b e + 5 B a e - 8 B b d\right )}{15 e^{5} \left (a + b x\right )} - \frac{4 b \left (3 a + 3 b x\right ) \sqrt{a^{2} + 2 a b x + b^{2} x^{2}} \left (3 A b e + 5 B a e - 8 B b d\right )}{15 e^{3} \sqrt{d + e x} \left (a e - b d\right )} - \frac{\left (2 a + 2 b x\right ) \left (A e - B d\right ) \left (a^{2} + 2 a b x + b^{2} x^{2}\right )^{\frac{3}{2}}}{5 e \left (d + e x\right )^{\frac{5}{2}} \left (a e - b d\right )} - \frac{2 \left (a^{2} + 2 a b x + b^{2} x^{2}\right )^{\frac{3}{2}} \left (3 A b e + 5 B a e - 8 B b d\right )}{15 e^{2} \left (d + e x\right )^{\frac{3}{2}} \left (a e - b d\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((B*x+A)*(b**2*x**2+2*a*b*x+a**2)**(3/2)/(e*x+d)**(7/2),x)
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Mathematica [A] time = 0.409851, size = 157, normalized size = 0.52 \[ \frac{2 \left ((a+b x)^2\right )^{3/2} \sqrt{d+e x} \left (-5 b^2 (-9 a B e-3 A b e+11 b B d)+\frac{45 b (b d-a e) (a B e+A b e-2 b B d)}{d+e x}-\frac{5 (b d-a e)^2 (a B e+3 A b e-4 b B d)}{(d+e x)^2}-\frac{3 (b d-a e)^3 (B d-A e)}{(d+e x)^3}+5 b^3 B e x\right )}{15 e^5 (a+b x)^3} \]
Antiderivative was successfully verified.
[In] Integrate[((A + B*x)*(a^2 + 2*a*b*x + b^2*x^2)^(3/2))/(d + e*x)^(7/2),x]
[Out]
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Maple [A] time = 0.014, size = 317, normalized size = 1. \[ -{\frac{-10\,B{x}^{4}{b}^{3}{e}^{4}-30\,A{x}^{3}{b}^{3}{e}^{4}-90\,B{x}^{3}a{b}^{2}{e}^{4}+80\,B{x}^{3}{b}^{3}d{e}^{3}+90\,A{x}^{2}a{b}^{2}{e}^{4}-180\,A{x}^{2}{b}^{3}d{e}^{3}+90\,B{x}^{2}{a}^{2}b{e}^{4}-540\,B{x}^{2}a{b}^{2}d{e}^{3}+480\,B{x}^{2}{b}^{3}{d}^{2}{e}^{2}+30\,Ax{a}^{2}b{e}^{4}+120\,Axa{b}^{2}d{e}^{3}-240\,Ax{b}^{3}{d}^{2}{e}^{2}+10\,Bx{a}^{3}{e}^{4}+120\,Bx{a}^{2}bd{e}^{3}-720\,Bxa{b}^{2}{d}^{2}{e}^{2}+640\,Bx{b}^{3}{d}^{3}e+6\,A{a}^{3}{e}^{4}+12\,Ad{e}^{3}{a}^{2}b+48\,Aa{b}^{2}{d}^{2}{e}^{2}-96\,A{b}^{3}{d}^{3}e+4\,Bd{e}^{3}{a}^{3}+48\,B{a}^{2}b{d}^{2}{e}^{2}-288\,Ba{b}^{2}{d}^{3}e+256\,B{b}^{3}{d}^{4}}{15\, \left ( bx+a \right ) ^{3}{e}^{5}} \left ( \left ( bx+a \right ) ^{2} \right ) ^{{\frac{3}{2}}} \left ( ex+d \right ) ^{-{\frac{5}{2}}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((B*x+A)*(b^2*x^2+2*a*b*x+a^2)^(3/2)/(e*x+d)^(7/2),x)
[Out]
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Maxima [A] time = 0.749571, size = 440, normalized size = 1.45 \[ \frac{2 \,{\left (5 \, b^{3} e^{3} x^{3} + 16 \, b^{3} d^{3} - 8 \, a b^{2} d^{2} e - 2 \, a^{2} b d e^{2} - a^{3} e^{3} + 15 \,{\left (2 \, b^{3} d e^{2} - a b^{2} e^{3}\right )} x^{2} + 5 \,{\left (8 \, b^{3} d^{2} e - 4 \, a b^{2} d e^{2} - a^{2} b e^{3}\right )} x\right )} A}{5 \,{\left (e^{6} x^{2} + 2 \, d e^{5} x + d^{2} e^{4}\right )} \sqrt{e x + d}} + \frac{2 \,{\left (5 \, b^{3} e^{4} x^{4} - 128 \, b^{3} d^{4} + 144 \, a b^{2} d^{3} e - 24 \, a^{2} b d^{2} e^{2} - 2 \, a^{3} d e^{3} - 5 \,{\left (8 \, b^{3} d e^{3} - 9 \, a b^{2} e^{4}\right )} x^{3} - 15 \,{\left (16 \, b^{3} d^{2} e^{2} - 18 \, a b^{2} d e^{3} + 3 \, a^{2} b e^{4}\right )} x^{2} - 5 \,{\left (64 \, b^{3} d^{3} e - 72 \, a b^{2} d^{2} e^{2} + 12 \, a^{2} b d e^{3} + a^{3} e^{4}\right )} x\right )} B}{15 \,{\left (e^{7} x^{2} + 2 \, d e^{6} x + d^{2} e^{5}\right )} \sqrt{e x + d}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b^2*x^2 + 2*a*b*x + a^2)^(3/2)*(B*x + A)/(e*x + d)^(7/2),x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.298421, size = 382, normalized size = 1.26 \[ \frac{2 \,{\left (5 \, B b^{3} e^{4} x^{4} - 128 \, B b^{3} d^{4} - 3 \, A a^{3} e^{4} + 48 \,{\left (3 \, B a b^{2} + A b^{3}\right )} d^{3} e - 24 \,{\left (B a^{2} b + A a b^{2}\right )} d^{2} e^{2} - 2 \,{\left (B a^{3} + 3 \, A a^{2} b\right )} d e^{3} - 5 \,{\left (8 \, B b^{3} d e^{3} - 3 \,{\left (3 \, B a b^{2} + A b^{3}\right )} e^{4}\right )} x^{3} - 15 \,{\left (16 \, B b^{3} d^{2} e^{2} - 6 \,{\left (3 \, B a b^{2} + A b^{3}\right )} d e^{3} + 3 \,{\left (B a^{2} b + A a b^{2}\right )} e^{4}\right )} x^{2} - 5 \,{\left (64 \, B b^{3} d^{3} e - 24 \,{\left (3 \, B a b^{2} + A b^{3}\right )} d^{2} e^{2} + 12 \,{\left (B a^{2} b + A a b^{2}\right )} d e^{3} +{\left (B a^{3} + 3 \, A a^{2} b\right )} e^{4}\right )} x\right )}}{15 \,{\left (e^{7} x^{2} + 2 \, d e^{6} x + d^{2} e^{5}\right )} \sqrt{e x + d}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b^2*x^2 + 2*a*b*x + a^2)^(3/2)*(B*x + A)/(e*x + d)^(7/2),x, algorithm="fricas")
[Out]
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x+A)*(b**2*x**2+2*a*b*x+a**2)**(3/2)/(e*x+d)**(7/2),x)
[Out]
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GIAC/XCAS [A] time = 0.307057, size = 686, normalized size = 2.26 \[ \frac{2}{3} \,{\left ({\left (x e + d\right )}^{\frac{3}{2}} B b^{3} e^{10}{\rm sign}\left (b x + a\right ) - 12 \, \sqrt{x e + d} B b^{3} d e^{10}{\rm sign}\left (b x + a\right ) + 9 \, \sqrt{x e + d} B a b^{2} e^{11}{\rm sign}\left (b x + a\right ) + 3 \, \sqrt{x e + d} A b^{3} e^{11}{\rm sign}\left (b x + a\right )\right )} e^{\left (-15\right )} - \frac{2 \,{\left (90 \,{\left (x e + d\right )}^{2} B b^{3} d^{2}{\rm sign}\left (b x + a\right ) - 20 \,{\left (x e + d\right )} B b^{3} d^{3}{\rm sign}\left (b x + a\right ) + 3 \, B b^{3} d^{4}{\rm sign}\left (b x + a\right ) - 135 \,{\left (x e + d\right )}^{2} B a b^{2} d e{\rm sign}\left (b x + a\right ) - 45 \,{\left (x e + d\right )}^{2} A b^{3} d e{\rm sign}\left (b x + a\right ) + 45 \,{\left (x e + d\right )} B a b^{2} d^{2} e{\rm sign}\left (b x + a\right ) + 15 \,{\left (x e + d\right )} A b^{3} d^{2} e{\rm sign}\left (b x + a\right ) - 9 \, B a b^{2} d^{3} e{\rm sign}\left (b x + a\right ) - 3 \, A b^{3} d^{3} e{\rm sign}\left (b x + a\right ) + 45 \,{\left (x e + d\right )}^{2} B a^{2} b e^{2}{\rm sign}\left (b x + a\right ) + 45 \,{\left (x e + d\right )}^{2} A a b^{2} e^{2}{\rm sign}\left (b x + a\right ) - 30 \,{\left (x e + d\right )} B a^{2} b d e^{2}{\rm sign}\left (b x + a\right ) - 30 \,{\left (x e + d\right )} A a b^{2} d e^{2}{\rm sign}\left (b x + a\right ) + 9 \, B a^{2} b d^{2} e^{2}{\rm sign}\left (b x + a\right ) + 9 \, A a b^{2} d^{2} e^{2}{\rm sign}\left (b x + a\right ) + 5 \,{\left (x e + d\right )} B a^{3} e^{3}{\rm sign}\left (b x + a\right ) + 15 \,{\left (x e + d\right )} A a^{2} b e^{3}{\rm sign}\left (b x + a\right ) - 3 \, B a^{3} d e^{3}{\rm sign}\left (b x + a\right ) - 9 \, A a^{2} b d e^{3}{\rm sign}\left (b x + a\right ) + 3 \, A a^{3} e^{4}{\rm sign}\left (b x + a\right )\right )} e^{\left (-5\right )}}{15 \,{\left (x e + d\right )}^{\frac{5}{2}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b^2*x^2 + 2*a*b*x + a^2)^(3/2)*(B*x + A)/(e*x + d)^(7/2),x, algorithm="giac")
[Out]